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Physics 15 Online
OpenStudy (kkbrookly):

Help please! I'll give a medal and fan

OpenStudy (kkbrookly):

You have a 2.00 kg block of lead. Lead melts at 327.5 Celsius. CPb = 130.0 J/kg * Celsius, and Hf for lead is 2.04 * 10^4 J/kg. Say you start at room temperature (25.0 Celsius). How much heat must you transfer to melt all the lead?

OpenStudy (kkbrookly):

@Directrix @divu.mkr @freckles @Godlovesme @perl @ybarrap

OpenStudy (kkbrookly):

Ummmmmmmmmmm???????

OpenStudy (kkbrookly):

@iambatman

OpenStudy (anonymous):

heat= heataddedToIncreaseTemp+ heataddedToMelt = 2kg*CPb*(327.5-25)+2kg*Hf 327.5x25.0=302.5 T= 302.5C q=2.00kg(130.0 kqc) (302.5c) q=H&M Q=78,650J Q=2.04x10^4 j/kg (2.00g)=40,800J Q=119,450J „³ 119,000J

OpenStudy (kkbrookly):

That's how much heat that would be transferred to melt all the lead?

OpenStudy (anonymous):

Yes which is 2kg*Cpb*(327.5-25)+2kg*Hf which is q=Heat transferred to melt the Lead

OpenStudy (kkbrookly):

So, 119,000 J is the answer?

OpenStudy (kkbrookly):

Thank you so much!

OpenStudy (anonymous):

Youre Welcome

OpenStudy (kkbrookly):

Wait, is the answer 119,450 J or 119,000 J? @Ijada123

OpenStudy (anonymous):

Its 119,000 J

OpenStudy (kkbrookly):

Alright. Thank you!

OpenStudy (anonymous):

Lml, Youre Welcome Again!

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