Help please! I'll give a medal and fan
You have a 2.00 kg block of lead. Lead melts at 327.5 Celsius. CPb = 130.0 J/kg * Celsius, and Hf for lead is 2.04 * 10^4 J/kg. Say you start at room temperature (25.0 Celsius). How much heat must you transfer to melt all the lead?
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Ummmmmmmmmmm???????
@iambatman
heat= heataddedToIncreaseTemp+ heataddedToMelt = 2kg*CPb*(327.5-25)+2kg*Hf 327.5x25.0=302.5 T= 302.5C q=2.00kg(130.0 kqc) (302.5c) q=H&M Q=78,650J Q=2.04x10^4 j/kg (2.00g)=40,800J Q=119,450J „³ 119,000J
That's how much heat that would be transferred to melt all the lead?
Yes which is 2kg*Cpb*(327.5-25)+2kg*Hf which is q=Heat transferred to melt the Lead
So, 119,000 J is the answer?
Thank you so much!
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Wait, is the answer 119,450 J or 119,000 J? @Ijada123
Its 119,000 J
Alright. Thank you!
Lml, Youre Welcome Again!
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