Find all polar coordinates of point P = (2, 14°).
is that not already polar coordinate form
do you know what polar co-ordinates look like?
No and no.
Wait..yes and no.
no (2,14) are Cartesian coordinates
It is but you have to find all ones equivalent? I think?
thats a 14 degrees though
oh - sorry - you are right
well for polar coordinates, to find them all you usually write it as \[(r,\theta + 2\pi(n))\]
r=2 theta=14
you already have polar coordinates so the only thing left would be to write it as I shown above using (r, theta + 2pin) where theta is in radians and n is any integer or (-r, theta) is the same as the plot of \[(r, \theta \pm \pi)\]
not sure what else to answer to your question sorry
We need to covert Cartesian to polar: |dw:1426043562297:dw| Using Euler's Identity: $$ e^{i\theta}=\cos\theta+i\sin \theta $$ In polar coordinates: $$ \large P=re^{i\theta}\\ \theta=\tan^{-1}{14\over2}=\tan^{-1}7=81.9~\text{degrees}\\ r=\sqrt{2^2+14^2}=14.14\\ \implies P=14.14e^{i81.9}\\ $$ Where \(r\) is the distance from the origin to P and \(\theta\) is the angle between the x-axis and segment \(r\) .
|dw:1426044052470:dw| see- http://en.wikipedia.org/wiki/Polar_coordinate_system#Complex_numbers
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