Question

evaluate the integral

Answer 1

\[\frac{ x^3 }{ 3 }\arctan - \frac{ 1 }{ 3 }\int\limits_{}^{}\frac{ x^3 }{ 1 + x^2 }\]

Answer 2

@Loser66

Answer 3

I am so lost

Answer 4

the original is \[\int\limits_{}^{}x^2\arctan(x)dx\]

Answer 5

If it helps, here is the solution and I don't understand why they are doing long division and how they got their answer

Answer 6

They did the long division to simplify the fraction into two. Then after that they did a u sub.

Answer 7

split x^3 as x^2 . x dx
then substitute x^2 = t
tdt/1+t
now its simple

Answer 8

oh gotcha @Luigi0210