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OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

How can I show the shortest distance between two points in R3 space is a straight line?

OpenStudy (anonymous):

I know it has to do with \[dS = \sqrt{dx^2+dy^2+dz^2}\] and maybe Euler's equation

OpenStudy (anonymous):

I'm thinking we let it depend on the parameter so maybe then we can define our function as \[f(t) = \sqrt{(x'(t))^2+(y'(t))^2+(z'(t))^2}\]

OpenStudy (anonymous):

So Euler's equation which is \[\frac{ \partial f }{ \partial y } - \frac{ d }{ dx } \frac{ \partial f }{ \partial y' } = 0\] right, so if we take the partial of f respect to x,y, and z we'll get 0. I think this is working out nicely, I'm going to see what I get as a final result

ganeshie8 (ganeshie8):

Are you kindof trying to find a path that minimizes the arc length integral ?

OpenStudy (anonymous):

Yup!

ganeshie8 (ganeshie8):

This looks interesting

ganeshie8 (ganeshie8):

If possible can you put the complete work when u finish

OpenStudy (anonymous):

Yeah sure, give me a bit, it might take me a while haha.

OpenStudy (anonymous):

I'm trying to do this problem, as I've been learning calculus variation and what not, it's very fascinating stuff.

ganeshie8 (ganeshie8):

You gona solve that differential eqn next is it

ganeshie8 (ganeshie8):

Find a curve \(r(t)\) such that below arclength integral is minimum : \[ L= \int_a^b \|r'(t)\|dt\]

OpenStudy (dan815):

why not start with showing the 2-D case

ganeshie8 (ganeshie8):

yeah im working on 2D case on my notes

OpenStudy (dan815):

kai made this tutorial a while back about euler-lagrange method one of its uses is to minimize integrals like this

OpenStudy (anonymous):

I did 2d

OpenStudy (anonymous):

\[dS = \sqrt{dx^2+dy^2}\] \[f = \sqrt{1+\left( \frac{ dy }{ dx }\right)^2}\] then you can use Euler's equation, and pretty simple from there, and you will get an equation of a straight line, I'll let you finish it on your own, or if you want the full work just ask. I'm sort of doing the same thing with space

OpenStudy (anonymous):

\[\int\limits_{x_1}^{x_2} \sqrt{1+ \left( \frac{ dy }{ dx } \right)^2dx}\] we let S be the minimum so we can define the function above, i think that's the hardest part about the problem really

OpenStudy (anonymous):

S ^

OpenStudy (anonymous):

Neat huh? :P

OpenStudy (anonymous):

Oh I just looked at the post dan made, kai actually did it for 2d, pretty much the same exact thing.

OpenStudy (anonymous):

http://puu.sh/gvtSk/18243df84c.png

ganeshie8 (ganeshie8):

Since we're trying to minimize the value of definite integral of \(f(x,y,y')\) between two points, \[df = f_x dx + f_y dy+f_{y'} dy' \implies \dfrac{df}{dx} = f_x + f_y y' + f_{y'} y'' \tag{1}\] eliminating \(y''\) we get \[ \dfrac{d}{dx}\left(f-y'\dfrac{\partial f}{ \partial y' } \right) - \dfrac{\partial f}{\partial x} = 0\]

OpenStudy (anonymous):

Ok so for space, \[\frac{ d }{ dt } \frac{ \partial f }{ \partial x' } \implies \frac{ x' }{ \sqrt{x'^2+y'^2+z'^2} } = C\] we can do this with y and z as well, so we get all the constants. \[\frac{ x' }{ C } = \frac{ y' }{ C_2 }\] doing the same thing with z, we can integrate and get a equation for a straight line in R3 I'm sure

ganeshie8 (ganeshie8):

nicee

OpenStudy (anonymous):

Yeah I think it works out pretty well :P

OpenStudy (anonymous):

Quick question, how do I add the dots for derivatives instead?

ganeshie8 (ganeshie8):

I think dots are not allowed in math group, you should use primes/subscripts for derivatives/partials :P

ganeshie8 (ganeshie8):

\[\huge \dot{y}\]

OpenStudy (anonymous):

Yeah well we use dots in physics :P, this is more so a physics question I think?

OpenStudy (anonymous):

Oh ok, haha thanks!

ganeshie8 (ganeshie8):

but you're in math group hmm

OpenStudy (anonymous):

Haha xD

OpenStudy (anonymous):

Ok prime is fine

OpenStudy (anonymous):

I got more questions, tougher than this...if you want to have a try at them, I'll be trying them later tomorrow

OpenStudy (anonymous):

Or I'll just post the questions I get stuck on :P

ganeshie8 (ganeshie8):

sure tag me in all questions, i remember doing few of these in my engineering math.. but really don't remember much.. il check out paul site and read some more in the evening

OpenStudy (anonymous):

Ok cool :P, I think it's about time I give you tough questions rather than the easy calc ones hehe.

OpenStudy (anonymous):

You should try to derive Euler's formula, it will be very useful, especially for these types of problems

ganeshie8 (ganeshie8):

i derived it already in my reply above using total derivative do you have a pdf/something thats really short to read ?

ganeshie8 (ganeshie8):

http://gyazo.com/0097701d005ec32fdb4761174e36851c this is equivalent to euler eqution

OpenStudy (anonymous):

I see, interesting and not really, I've been just reading my book, but I'm sure there are many calculus variation pdfs out there

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