What is the distance between (5, 6, 4) and (4, 4, 2)? Round to the nearest tenth of a unit
basically the same as the 2d distance formula http://www.calculatorsoup.com/images/equations/distance-three-coordinates.png
wat
did you never have to find the distance between, say (2,1) and (5,6)?
let's make \((x_2,y_2,z_2)= (5, 6, 4) \\(x_1,y_1,z_1)= (4, 4, 2) \) plug and chug
so you change the x^2, y^2, z^2 for (4,4,2)
hold up time for more color coding
pls dont bib ily
but yeah, just put the green shape into the green hole just like kindergarten ily2
ok I'll write it out
I'll start you off. \(\sqrt{(5-4)^2+(y_2-y_1)^2+(z_2-z_1)^2}\)
wait im confused now
had to switch to a new browser
sorry bibby :c
why apologize lol
it makes sense, I think
it might make more sense if you use an online calculator and look at the finished product and then work backwards
Oh it's 3? I saw that as an answer somewhere else
3 isnt an option, ;-;
that is the answer, ye
wtf
I'm going to beat you up if it didn't copy the negatives again
IM SORRYYYYYYYYYYYYYYYYY
hahahaha
why do you do this to me
ILY
\((\color{green}{x_2},\color{cyan}{y_2},\color{red}{z_2})= (\color{green}5, \color{cyan}{-6}, \color{red}{4}) \\(\color{purple}{x_1},\color{blue}{y_1},\color{pink}{z_2})= (\color{purple}4,\color{blue}{-4}, \color{pink}{-2})\\ \large d=\sqrt{(\color{green}{x_2}-\color{purple}{x_1})^2+(\color{cyan}{y_2}-\color{blue}{y_1})^2+(\color{red}{z_2}-\color{pink}{z_2})^2}\) same method, different numbers
cries
erases everything
theeere theeere
i have no idea
|dw:1426049970569:dw| start by evaluating that parentheses, we'll add each piece
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