Question

If x^3+y^3=9 and dx/dt=4, find dy/dt when x=2

Answer 1

I think its -16

Answer 2

how did you the answer? can you please explain

Answer 3

that is the correct answer

Answer 4

when x = 2,

y^3 = 9 - 8 = 1==> y = 1

differentiating implicitly

3x^2 dx/dt + 3y^2dy/dt = 0

=>x^2 dx/dt + y^2 dy/dt = 0

substitute x = 2, y = 1 and dx/dt = 4

(4)(4) + (1)dy/dt = 0

dy/dt = -16

Answer 5

Can i have a medal

Answer 6

thank you!

Answer 7

No thank you