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Mathematics 13 Online
OpenStudy (anonymous):

Medal OR Fan I have a question that has to do with slant height ill post the question in just a second

OpenStudy (anonymous):

OpenStudy (igreen):

Use the Pythagorean Theorem

OpenStudy (anonymous):

igreen help me

OpenStudy (igreen):

Height = 8 The triangle in the middle's base is half the triangular prisms base.. 12 / 2 = 6 We have the two legs(6 and 8) now let's find the hypotenuse. \(a^2 + b^2 = c^2\) \(6^2 + 8^2 = c^2\) Solve for 'c'

OpenStudy (ahsome):

Simply use the pythagorous theorum: \[c^2=a^2+b^2\] Where: \(a^2\) and \(b^2\) are any two sides of the triangle: \(c^2\) is the hypotenuse \[c^2=a^2+b^2\] Substitute your values, and solve \[c^2=a^2+b^2\]\[c^2=12^2+8^2\]\[c^2=208\]\[c=\sqrt{208}\]\[c=14.4222051\]\[c\approx14\] So, the slant height is 14

OpenStudy (igreen):

@Ahsome We're not supposed to give answers..plus that's incorrect.

OpenStudy (anonymous):

My brain just popped

OpenStudy (ahsome):

Except, you would use 6, and not 12. This is because 12 is the whole base, while you only need half

OpenStudy (igreen):

Pyramid base = 12 Triangle in the middle's base = half the pyramid's base. 12 / 2 = 6 Therefore, the triangle's base is 6.

OpenStudy (ahsome):

@Hayhaywild002, have you learnt how to use Pythagorous THeorum before?

OpenStudy (igreen):

Can you simplify \(6^2\) and \(8^2\)? @Hayhaywild002

OpenStudy (anonymous):

so your saying igreen that....... \[36+64=c^2\]

OpenStudy (igreen):

Yep

OpenStudy (ahsome):

@Hayhaywild002 , yes :)

OpenStudy (igreen):

Now add 36 + 64

OpenStudy (ahsome):

Then square root the value

OpenStudy (anonymous):

Do i have to find the square root of it ??

OpenStudy (igreen):

Yep

OpenStudy (igreen):

Yes, now square both sides: \(c = \sqrt{36 + 64}\)

OpenStudy (anonymous):

C= 100 the the square root of that is 10?

OpenStudy (ahsome):

Yes

OpenStudy (anonymous):

What your saying that i got it right?!!!!

OpenStudy (igreen):

Yep, you got it.

OpenStudy (ahsome):

Yes :)

OpenStudy (anonymous):

ok so who wants a medal and who wants me to fan them

OpenStudy (anonymous):

Its the reward for helping me

OpenStudy (ahsome):

Give it to @iGreen

OpenStudy (igreen):

You can give 2 medals

OpenStudy (anonymous):

I can?

OpenStudy (anonymous):

It won't let me

OpenStudy (igreen):

Yeah, just make sure you haven't given any medals yet. Then open the same post in a new tab and give both of us a medal..it only works on different people so you can't give 2 medals to one person.

OpenStudy (igreen):

I just gave a medal to you and @Ahsome

OpenStudy (ahsome):

Thx @iGreen ;)

OpenStudy (igreen):

Np :P

OpenStudy (anonymous):

thx guys

OpenStudy (anonymous):

14 cm

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