Question

Write the equation of the line, in standard form, that passes through the origin and is parallel to x + y = 6

Answer 1

@sleepyjess @hartnn

Answer 2

Ok, what is the slope of the given line?

Answer 3

Slope is -1 and y-intercept is 6

Answer 4

Good.. :)

Answer 5

Yes, so we know that the slope of the unknown line is -1, and it passes through the origin, so the y-intercept is 0.

Answer 6

So how would this one be set up?

Answer 7

Well, we would use slope intercept form first again

Answer 8

y=-1x+0 ..?

Answer 9

Yes, now move the -x to the other side

Answer 10

-x+y=0 but multiply by -1 so x-y=0. But where does the 6 go?

Answer 11

Be careful..!! :P

Answer 12

We need to do the opposite

Answer 13

Now what? Lol

Answer 14

you will add \(x\) both the sides and not subtract..

Answer 15

Huh?

Answer 16

???

Answer 17

@eta What do I need to do?

Answer 18

\(y = -x\)

Answer 19

Add \(x\) dear..!!

Answer 20

x+y=0

Answer 21

\[y + x = -x + x \implies x+y = 0\]

Answer 22

Good, up to the mark..

Answer 23

But what do I need to do with the 6?

Answer 24

What?

Answer 25

Write the equation of the line, in standard form, that passes through the origin and is parallel to x + y = 6

Answer 26

See, there are two equations, or you can say you have two lines..

Answer 27

There can't be two equations

Answer 28

One line you are totally given, ie x+y =6

Now, you are finding the equation of another line which is parallel to this line..