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Mathematics 21 Online
OpenStudy (anonymous):

A video sharing website starts with 20,000 members. Each year it loses 25% of the members, but adds 10,000 new members after the reduction. Write a recursive rule to find the number of members for any year.

OpenStudy (anonymous):

@LeeEtchison @bohotness

OpenStudy (anonymous):

@ambius @whydoihavetosignup1 @RAINIAR

OpenStudy (anonymous):

so, essentially there are two components to the change in population - probably a couple of ways to approach it... however, what we are looking for is an equation in the form of: \[P_{n+1} = f(P_n)\] meaning the next value of the population is equal to a function of the current value. I'll show you the first value: \[P_{0} = 20000\] what would \[P_1\] equal?

OpenStudy (anonymous):

these are the choices they gave me

OpenStudy (anonymous):

Pleeeaasssee Hellpp

OpenStudy (anonymous):

Sorry... lots of stuff at once... okay so you notice I started the equation considering the "next" value in the equation - P(n+1). However, you can look at the equation interms of the "previous" value instead. This seems a little confusing, but it's not too bad once you get the hang of it. So, instead of over-complicating it, I'll give you a hint. The initial population is 20000, so: \[P_1 = 20000\] If I were to calculate the change in population after a year to determine P2 using the value of P1, how would I calculate it?

OpenStudy (anonymous):

Any ideas?

OpenStudy (anonymous):

Here's another hint; I can't give you much more than this without straight-up giving you the answer: \[P_2 = 0.75P_1 + 10000\]

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