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will $ 6 \sqrt{x + 3} + 4 = 16$ work for the equation with the extraneous solution

Question

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will $ 6 \sqrt{x + 3} + 4 = 16$ work for the equation with the extraneous solution

anonymous · Answer

@Directrix

anonymous · Answer

@SolomonZelman

anonymous · Answer

someone

directrix · Answer

The equation you posted has one solution and it is not extraneous:

6*sqr(x + 3) + 4 = 16

x = 1

anonymous · Answer

ok so I can use that for the non-extraneous equation. can you help me create an extraneous one?

anonymous · Answer

i am having a hard time making one @Directrix

directrix · Answer

Look and see how your text defines extraneous solution.

Does an extraneous solution also include no solution? I don't think so but check anyway, okay?

anonymous · Answer

ok give me a sec

anonymous · Answer

this is the only thing in my lesson that discusses 'extraneous'

The extraneous solution came from squaring both sides. Both 3^2 = 9 and (–3)^2= 9, but in checking the solution, the positive square root was used.

and i have never seen it in previous lessons either

anonymous · Answer

refresh to get rid of diamons

anonymous · Answer

its confusing not much info and its asking me questions about it

directrix · Answer

If you were allowed to add another x variable, it would be easy to find an extraneous solution.

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