Question

Determine which of the following are the solutions to the equation below.
x^2=11

Answer 1

what do you think

Answer 2

any attempt

Answer 3

i have no clue how to do it

Answer 4

how do we solve \[x^2=1\]

Answer 5

idk

Answer 6

ok let's ask a different way
what number is i square it gives me one

Answer 7

so?

Answer 8

do we have \[1^2=1~~and~~(-1)^2=1\]

Answer 9

so two number result in 1

Answer 10

so 11^2 = 22

Answer 11

no that is now my point

Answer 12

my point is some number or numbers if i square it i will get

Answer 13

when we have \[x^2=a\]
to find what x is we take square root of both sides \[\sqrt{x^2}=\sqrt{a}\]
square root cancels with the square
then get only
\[|x|=\sqrt{a}\]
which is the same as
\[x=\pm\sqrt{a}\]

Answer 14

in your example you have a=11
so just replace a with 11

Answer 15

so the answer is 11

Answer 16

no! look carefully at what i did and do the same

Answer 17

take the square root of both sides
first

Answer 18

\[\sqrt{x^2} and \sqrt{11}\]

Answer 19

put equal sign \[\sqrt{x^2}=\sqrt{11}\]

Answer 20

go on...

Answer 21

\[\sqrt{x^2}=\sqrt{11}\]

Answer 22

follow and do the rest

Answer 23

\[\left| x \right|=\sqrt{11}\]

Answer 24

aha..

Answer 25

\[x=\pm \sqrt{11}\]

Answer 26

is that right

Answer 27

yes

Answer 28

and thats all right

Answer 29

yes