Ca + N2H2O -------> Ca(OH) 2 +H2 Given the balaanced chemical equation : What is the total number of moles of Ca that will react with 6 moles of water?
Something looks off about your equation, what happens to the N?
Did you mean Ca+2H2O>>>>>Ca(OH)2+H2?
Oh yeah lol sorry there is no N, good catch i was suprised
Well, then it's pretty simple from here. The current balanced equation has 2 moles of water and 1 mole of Ca. If you want 6 moles of water, you multiply the co efficient by 3... Ca=1x3=?
What how did you get 2 moles of water sorry. And 3 moles of Ca
Ca+2H2O>>>>>Ca(OH)2+H2 there is a two in front of H2O
that represents 2 moles
It was balanced already im guessing.
if they suddenly wanted 6 moles, you would multiply the whole equation by three.
so...you need 3 moles of Ca
Ok thanks. Can i ask one more and tell you the answer to see if i get it write
I did not pay attention in class today
go ahead
Given the balanced cehmical equations: What is the total numbero f mles of NO2 that will be produced from 5 moles of N205? 2N205(G)------> 4 NO2(G) + O2(G)
Is the answers 1,25 moles of NO2
1.25
Your current equation has 2 moles of N2O5, what would you multiply to get the number to 5?
Im lost
2.5 ?
yes. so there are also 4 moles of NO2. 4x2.5=?
10
Is that it?
yes
Should i write it as a fraction or a decimal
well the number "10" doesn't have to be in a fraction or decimal
May i ask one more this one seems a little harder
Thanks for telling me
Wait would the answer be 10 OR 2.5?
10 moles
2.5 was just the ratio factor
But the first problem we used same equation
2h20 * 3 = 6 so it would be 3 moles
yes that was just a coincident 3 as the scale factor, but also 3 moles of Ca.
Oh lol ok thanks
May i ask one more!
of course
Given the balanced chemical equation: How many moles of C02 will be produces from reeacting 7.4 moles of 02 CH4 (G) + 202 (G) -----> C02(G) + 2H20(I)
There are two moles of O2 and 1 mole of Co2. If there are 7.4 moles of O2.. you simply do 7.4/2=
Lol thank you, sorry i didnt pay attention today still learning it. That sounds very easy, thanks wouldnt have done it without you
its alright. feel free to tag me onto more questions :)
Thank you!
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