Question

Help with trig fundamentals

Answer 1

Use algebra to rewrite the following identity in 2 different forms. tan^2(θ) + 1 = sec^2(θ)

Answer 2

tan^2(Theta)=sec^2(theta)-1

Answer 3

@freckles what would the other one be?

Answer 4

I cant think of anything else it changes too

Answer 5

@Zarkon hes a pro ik he can do it

Answer 6

what is the beta sign or delta sign would the mean X?

Answer 7

yeh its basically like saying x

Answer 8

well you could divide both sides by tan^2(theta)

Answer 9

do you know Pythagorean identities

Answer 10

\[\sin^2(x)+\cos^2(x)=1 \\ \text{ divide both sides by} \cos^2(x) \\ \tan^2(x)+1=\sec^2(x)\]
you can also choose to divide both sides by sin^2(x)

Answer 11

Well I am confused this is already in pythagorean identity so i just switched it to solve for tan s: I am a little bit confused on what you did with dividing tan^2(theta) and sin^2(theta)

Answer 12

\[\tan^2(x)+1=\sec^2(x) \\ \frac{\sin^2(x)}{\cos^2(x)}+1=\frac{1}{\cos^2(x)} \\ \frac{\sin^2(x)+\cos^2(x)}{\cos^2(x)}=\frac{1}{\cos^2(x)}\]
or multiply both sides by cos^2(x)

Answer 13

i would have never been able to help lol

Answer 14

Ugh why am i so confused looking at that

Answer 15

is it because I replaced 1 with cos^2(x)/cos^2(x) ?

Answer 16

I am so confused how sin and cos became involved. Like Memorizing the identities is alright, but i have issues with what you just did

Answer 17

so you aren't familiar with tan=sin/cos
and sec=1/cos
and csc=1/sin ?

Answer 18

quotient properties. Man I forgot bout those

Answer 19

So much to remember thats on me lol. I forgot

Answer 20

mr. dark i must leave you in the dark
peace for now :p

Answer 21

alright :p bye thanks for the help

Answer 22

khanacademy.com

Answer 23

is a good site