Question

A pilot can travel 500 miles with the wind in the same amount of time as 340 miles against the wind. Find the speed of the wind if the pilots speed in still air is 210 mph. please help!

Answer 1

@AlexandervonHumboldt2 @dan815 @Joel_the_boss @Val14

Answer 2

@Jamielynne @josedavid @Elwell98 @Quan99 @k12andstudyislandhelp

Answer 3

idk srry

Answer 4

k thanks

Answer 5

@bohotness @fashionlove @Bee_see @blah124 @KierseyClemons @bibby

Answer 6

@rachelledelija123 @Squirrels @sissyedgar @W.W.G.D @esam2 @linn99123 @Quan99

Answer 7

@NaomiBell1997 @nothingwasthesame @goatgal102

Answer 8

@InExileWeTrust @yoyogators @owls2001 @xokatexo @zach1751

Answer 9

@Answers101

Answer 10

I tink its 370! Bbt im not sure!

Answer 11

but*

Answer 12

ok thanks!

Answer 13

nope :( sadly it's not :(

Answer 14

i have 2 more trys tho

Answer 15

do u know what else it might be?

Answer 16

@Gebooors @CloverRacer @CausticSyndicalist @mathmath333 @luckycoins888 @MikeyMaximum

Answer 17

lemme think for a min k?

Answer 18

try 120

Answer 19

ok

Answer 20

no, now i have one more try... @luckycoins888

Answer 21

u there?

Answer 22

@mwill<3 @annon1123 @Molly_Qian @Loser66 @sleepyjess

Answer 23

huh?

Answer 24

:d yes you rright :D

Answer 25

\(\large \color{black}{\begin{align}
\normalsize \text{let the speed of the wind be } x\quad mph\hspace{.33em}\\~\\
\normalsize \text{let the speed of the plane in still air be } y\quad mph\hspace{.33em}\\~\\
\normalsize \text{pilot speed with the wind}=(x+y) \quad mph\hspace{.33em}\\~\\
\normalsize \text{pilot speed against the wind}=(y-x) \quad mph\hspace{.33em}\\~\\
t_{1}=t_2\hspace{.33em}\\~\\
\dfrac{500}{x+y}=\dfrac{340}{y-x}\hspace{.33em}\\~\\
\normalsize \text{but the speed of the plane in still air is given } y=210 \quad mph\hspace{.33em}\\~\\
\dfrac{500}{x+210}=\dfrac{340}{210-x}\hspace{.33em}\\~\\
\normalsize \text{find x} \hspace{.33em}\\~\\
\end{align}}\)