find the derivative of (10,000)/(9+4e^(-.2t))
with respect to what ?
if it is not with respect to 'e' then you are differentiating a constant.
it's actually e^-.2t sorry
\(\Large\color{black}{ \displaystyle y=e^{-.2t}}\)
well, you can just do the derivative of e^t is e^t, but then use the chain rule for the exponent.
\[\frac{ 10,000 }{ 9+4e ^{-.2t} }\]
\(\Large\color{black}{ \displaystyle y=10,000\left(9+4e^{-.2t}\right)^{-1}}\) this is how I would write it before differentiating
\(\large\color{black}{ \displaystyle y'=10,000(-1)\left(9+4e^{-.2t}\right)^{-1-1}~\times~\frac{d}{dx}\left[9+4e^{-2.t}\right]}\)
or, if you want you can do the quotient rule, if you feel that is easier
maybe lets differentiate first, the \(\large\color{black}{ \displaystyle \left(9+4e^{-.2t}\right)^{-1}}\)
so i did it the way you said to by differentiating and it was way easier than the quotient rule
what did you get?
i figured out the answer. i think the quotient rule was just confusing me.
in the end i got \[\frac{ 80,000e ^{-.2t} }{ 9+4e ^{-.2t} }\]
I think the bottom should be squared, because you are applying the power rule to \(\large\color{black}{ \displaystyle \left(9+4e^{-.2t}\right)^{-1}}\) and the 80000 should be 8000, as you are multiplying the 10000 coefficient times 0.2 and you are right that it is positive, because negative that is from the exponent's chain rule, and the negative that is from the power rule\ CANCEL each other out.
\(\large\color{black}{ \displaystyle y'=10,000(-1)\left(9+4e^{-.2t}\right)^{-1-1}~\times~\frac{d}{dx}\left[9+4e^{-2.t}\right]}\) \(\large\color{black}{ \displaystyle y'=10,000(-1)\left(9+4e^{-.2t}\right)^{-2}~\times~\left[4e^{-2.t}\right] \times -.2t}\) and on...
cool thank you :)
yes, .2 times 4 = 0.8 amd 10000 times 0.8 = 8000
that is why the coefficient in the answer is 8000
bye
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