f(x) = log2(x – 3) + 1 how do you find the domain and the range?
Do you know the transformations of the log function
log2(x)?
the domain is (3,infinity) When you have just have \[\log_{2} \] your domain is (0, infinity)
when you do you shift the graph to the right 3 units
log2(x-3) i mean
+1 you move up
is there any way of knowing without having to see or make a graph?
Do want an algebraic way?
yes please something that does not require me having to make a graph in order to find the answer
i mean, you dont necessarily gave to graph it. just using knowledge of the log function you know the domain can never be negative. You can just apply the transformations and know generally the shape in your head.
domain is all the possible x values range is all the possible y values
log of a negative number is defined so log(x-3) <--- you gotta make sure you dont take log of negative number so x be 3 or more, if its less its a negative number so domain(or possible values of x) x>=3,
log of a negative number is undefined
now lets see the lowest point of this log must be at the lowest point of the x
oh sry a slight mistake here!
log(0) is undefined too
so x>3
x=3 is not allowed either
log function goes from -inf to inf
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