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Mathematics 20 Online
OpenStudy (daniellelovee):

f(x) = log2(x – 3) + 1 how do you find the domain and the range?

OpenStudy (anonymous):

Do you know the transformations of the log function

OpenStudy (daniellelovee):

log2(x)?

OpenStudy (anonymous):

the domain is (3,infinity) When you have just have \[\log_{2} \] your domain is (0, infinity)

OpenStudy (anonymous):

when you do you shift the graph to the right 3 units

OpenStudy (anonymous):

log2(x-3) i mean

OpenStudy (anonymous):

+1 you move up

OpenStudy (daniellelovee):

is there any way of knowing without having to see or make a graph?

OpenStudy (anonymous):

Do want an algebraic way?

OpenStudy (daniellelovee):

yes please something that does not require me having to make a graph in order to find the answer

OpenStudy (anonymous):

i mean, you dont necessarily gave to graph it. just using knowledge of the log function you know the domain can never be negative. You can just apply the transformations and know generally the shape in your head.

OpenStudy (dan815):

domain is all the possible x values range is all the possible y values

OpenStudy (dan815):

log of a negative number is defined so log(x-3) <--- you gotta make sure you dont take log of negative number so x be 3 or more, if its less its a negative number so domain(or possible values of x) x>=3,

OpenStudy (dan815):

log of a negative number is undefined

OpenStudy (dan815):

now lets see the lowest point of this log must be at the lowest point of the x

OpenStudy (dan815):

oh sry a slight mistake here!

OpenStudy (dan815):

log(0) is undefined too

OpenStudy (dan815):

so x>3

OpenStudy (dan815):

x=3 is not allowed either

OpenStudy (dan815):

log function goes from -inf to inf

OpenStudy (dan815):

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