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Discrete Math
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If n = 2^10 * 3^14* 5^8, how many of the natural-number factors of n are multiples of 150?
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\[150 = 6*25 = 2*3*5^2\] that means : the exponent on \(2\) can be between \(1\) and \(10\) = \(10\) ways the exponent on \(3\) can be between \(1\) and \(14\) = \(14\) ways the exponent on \(5\) can be between \(2\) and \(8\) = \(7\) ways then total number of factors that are multiples of \(150\) would be : \(10\times 14\times 7\)
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