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OpenStudy (howard-wolowitz):
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OpenStudy (howard-wolowitz):
@pitamar
OpenStudy (howard-wolowitz):
so k=1300
OpenStudy (howard-wolowitz):
would it also y always be in fraction form
OpenStudy (anonymous):
if y varies inversely with x then yes. Always makes sure you read what varies with what and in in what way.
So, what do you think?
OpenStudy (howard-wolowitz):
d
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OpenStudy (anonymous):
what is the form of y varies inversely with x? including k
OpenStudy (howard-wolowitz):
I dont think x would be on the
OpenStudy (anonymous):
Is it \(y=\frac{k}{x}\) or \(y=\frac{x}{k}\)?
OpenStudy (howard-wolowitz):
y = x/k
OpenStudy (howard-wolowitz):
well actually no its the other one
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OpenStudy (howard-wolowitz):
i messed up
OpenStudy (howard-wolowitz):
y = k/x
OpenStudy (anonymous):
Yes, exactly. y = x/k is actually a direct inversion in disguise, because dividing by a constant is just like multiplying by a constant.
OpenStudy (anonymous):
Right, so if you plug 1300 in, what do you get?
OpenStudy (howard-wolowitz):
but you said that was wrong earlier
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OpenStudy (anonymous):
No, k = 1300 is fine, the question is what is the answer
OpenStudy (anonymous):
if we plug
$$
y = \frac{k}{x} \implies y=\frac{1300}{x}
$$
That is not d
OpenStudy (howard-wolowitz):
its b
OpenStudy (anonymous):
Right
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