Question

For f(x)=1-x/1+x and g(x)=x/1+x and , find the simplified form for f [g(x)] and state the domain. @freckles @radar @ganeshie8

Answer 1

f[g(x)] means where there is x you put g(x), can you do that

Answer 2

you put g(x) in x of f(x)

Answer 3

yes I can, but i am not sure how to simplify the function once i place g(x) into f(g(x)) @Percy*

Answer 4

@ikram002p

Answer 5

@SithsAndGiggles

Answer 6

\[f(x)=\frac{1-x}{1+x}\\[0.4em]\]\[g(x)=\frac{x}{1+x}\]

Answer 7

\[\large f[g(x)]=\frac{1-\frac{x}{1+x}}{1+\frac{x}{1+x}}\]

Answer 8

\[\large f[g(x)]=\frac{1-\frac{x}{1+x}}{1+\frac{x}{1+x}}\]
\[\large f[g(x)]=\frac{\frac{1+x}{1+x}-\frac{x}{1+x}}{\frac{1+x}{1+x}+\frac{x}{1+x}}\]
\[\large f[g(x)]=\frac{\frac{1+x-x}{1+x}}{\frac{1+x+x}{1+x}}\]
\[\large f[g(x)]=\frac{1+x-x}{1+x+x}\]
\[\large f[g(x)]=\frac{1}{1+2x}\]

Answer 9

what I don't get is, why is this a calculus question ?

Answer 10

im inap calculus ab and its part of this long review I just wasn't sure about the simplification
its been a really long time since I've seen a composition question

Answer 11

thanks so much @*-*

Answer 12

@((*-*))

Answer 13

I am untaggable, xd

Answer 14

anyways.... bye, and you welcome!

Answer 15

I got a notification

Answer 16

i tried lol thanks

Answer 17

but, you will never ever ever ever ever ever^(infinity) get my name underlined, and clickable.

Answer 18

ya i even clicked the link for ur user and it didnt work when I was trying to type it in here

Answer 19

its ok haha @Nnesha