Question

Homework help on coding exercises. I did two exercises from Java AU Naturel book for homework. I need help fixing my program. I did exercises 7.6 and 7.13

Answer 1

My code:
public class PersonnelDataV3
{
private Buffin itsFile = new Buffin ("workers.txt");
//private String itsLastN = null; // assuming all workers have a last name
private int itsSizeOfWorkers = 100; // supposing we have 100 workers,
/** Add to Listing 7.3 coding to tell whether the workers are in increasing
* order of names as determined by compareTo.
* A sequence of less than two values is considered to be in increasing order in any case.
* */
public String findEarliestWorker()
{ Worker answerSoFar = new Worker (itsFile.readLine()); //1
if (answerSoFar.getName() == null) //2
return "no workers!"; //3
else //4
{ Worker data = new Worker (itsFile.readLine()); //5
while (data.getName() != null) //6
{ if (data.compareTo (answerSoFar) < 0) //7
answerSoFar = data; //8
data = new Worker (itsFile.readLine()); //9

} //10
return answerSoFar.getName() + " is first of all."; //11

} //12

}

/** Here, I added another method, where Ican use compareTo to see if workers are increaseing
* in order of names , the compareTo is in charge of that.
*
*/

public String ifOrdered(Object par)
{
String comparison = "";
String LastN = null;
Worker one = (Worker) par;
Worker two = (Worker) par;
int w = 0; // w for workers

// when we have less than 100 workers
while (w < itsSizeOfWorkers)
{ if ( one.LastN.compareTo (two.LastN) < 0)
{ comparison = false;

}

else if (one.LastN == null || two.LastN == null)
{ comparison = true;

}
// adding onemore value to the current
w++;
}
return comparison;
}
}

Answer 2

Here is the ListingIhave to add to an the wording of the exercise 7.13
Listing:
public class PersonnelData
{
private Buffin itsFile = new Buffin ("workers.txt");
/** Read a file and return the name of the Worker that is
* alphabetically first. */
public String findEarliestWorker()
{ Worker answerSoFar = new Worker (itsFile.readLine()); //1
if (answerSoFar.getName() == null) //2
return "no workers!"; //3
else //4
{ Worker data = new Worker (itsFile.readLine()); //5
while (data.getName() != null) //6
{ if (data.compareTo (answerSoFar) < 0) //7
answerSoFar = data; //8
data = new Worker (itsFile.readLine()); //9
} //10
return answerSoFar.getName() + " is first of all."; //11
} //12
} //======================
}

Answer 3

Exercise 7.13** Add to Listing 7.3 coding to tell whether the workers are in increasing
order of names as determined by compareTo. A sequence of less than two values is
considered to be in increasing order in any case.

Answer 4

The PersonnelDataV3 means that it is exercise 7.13

Answer 5

OK, what probelm are you having with it?

Answer 6

I keep getting an error message saying that it can't fins a symbol. I tried defining it..

Answer 7

Which symbol?

Answer 8

See, part of the probnlem is that with a regular pase of the code I can't test it. When I copy it, al I get is this:

public class PersonnelDataV3 { private Buffin itsFile = new Buffin ("workers.txt"); //private String itsLastN = null; // assuming all workers have a last name private int itsSizeOfWorkers = 100; // supposing we have 100 workers, /** Add to Listing 7.3 coding to tell whether the workers are in increasing * order of names as determined by compareTo. * A sequence of less than two values is considered to be in increasing order in any case. * */ public String findEarliestWorker() { Worker answerSoFar = new Worker (itsFile.readLine()); //1 if (answerSoFar.getName() == null) //2 return "no workers!"; //3 else //4 { Worker data = new Worker (itsFile.readLine()); //5 while (data.getName() != null) //6 { if (data.compareTo (answerSoFar) < 0) //7 answerSoFar = data; //8 data = new Worker (itsFile.readLine()); //9 } //10 return answerSoFar.getName() + " is first of all."; //11 } //12 } /** Here, I added another method, where Ican use compareTo to see if workers are increaseing * in order of names , the compareTo is in charge of that. * */ public String ifOrdered(Object par) { String comparison = ""; String LastN = null; Worker one = (Worker) par; Worker two = (Worker) par; int w = 0; // w for workers // when we have less than 100 workers while (w < itsSizeOfWorkers) { if ( one.LastN.compareTo (two.LastN) < 0) { comparison = false; } else if (one.LastN == null || two.LastN == null) { comparison = true; } // adding onemore value to the current w++; } return comparison; } }

A real mess.

You need to put \(\text{```}\) on a blank line above and below the code block. That is the accent on the ~ key. Then it formats the code:

```
public class Blaa(some stuff)
{
code;
code;
code;
}
```

See how that keeps the formatting? it also makes it copy and paste properly.