Question

You have three beakers, each containing a solution of fructose.

The first beaker contains 125 ml and is 2.14 M fructose.

The second beaker contains 125 mL and is 1.02 M fructose.

The third beaker contains 100 mL and is 2.89 M fructose.

If you were to mix all three beakers together, what would be the concentration of fructose in the resulting solution?

Answer 1

What's going to stay the same throughout this question is the total number of moles: the moles of fructose in your 3 individual solutions will equal the moles of fructose in your final solution. So you can use the following equation:

\[M_1 V_1+M_2 V_2 + M_3 V_3=M_4(V_1+V_2+V_3)\]
Where the M's are concentrations and V's are volumes. You're given all the information in the question, so just solve for M(4)!

Answer 2

@matt101 that didn't come out to right answer. The correct answer is 1.95M and I have 1.42M

Answer 3

Hmm I got 1.95 M when I solved it. Double check your work to make sure your numbers are right!

Answer 4

@matt101 Found my problem. Thanks!

Answer 5

No problem!