Question

Simplify completely the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power times y to the 2nd power all over 5 times x to the third power times y

Answer 1

@welshfella

Answer 2

yes?

Answer 3

can you help me @pandaluvs

Answer 4

I'm sorry i suck at this stuff =)

Answer 5

do u know anyone that can help me

Answer 6

please

Answer 7

@MarshallEatsFood @Great_And_Powerful @ribhu @Love_Ranaa

Answer 8

@k_lynn ??

Answer 9

@StudyGurl14

Answer 10

I need help with 5 questions like this anyone please omgg

Answer 11

Like this?
\(\Large \frac{10x^6y^3+20x^3y^2}{5x^3y}\)
10 times x to the 6th power times y to the third power plus 20 times x to the third power times y to the 2nd power all over 5 times x to the third power times y

Answer 12

yes

Answer 13

First step. Factor of \(\large 5x^3y\) from the numerator so you can eliminate the denominator.
\(\huge\frac{10x^6y^3+20x^3y^2}{5x^3y}\rightarrow\frac{5x^3y(2x^3y^2+4y)}{5x^3y}\rightarrow ?\)
Can you do the rest?

Answer 14

no i really dnt get this stuff

Answer 15

nd i also need help with four more

Answer 16

the \(5x^3y\) in the numerator and the denominator can cancel out because...
\(\Large \frac{5x^3y}{5x^3y}=\large1\)
So...you can simplify the expression into...
\(\large 2x^3y^2+4y\)

Answer 17

That's it, unless they also want you to factor out the 2y

Answer 18

thank you

Answer 19

You're welcome.