i need help finding derivatives
\[f(x)=xe^{-9x}\]
i need to find 3 derivatives
what do you mean by find 3 derivatives?
f' f'' and f'''
so? go ahead, f'=?? product rule
\[-9x*e^{-9x}\]
i mean -9 e^-9x
\(f'(x) = x'*e^{-9x}+x (e^{-9x})' = e^{-9x} -9xe^{-9x}\)
does that = \[e^{-9x}(x-9)\]
F'=(1-9x)*e^-9x
check again, my answer is ok:)
f'' = \[(x-1)(1-9x)e^{-9x}\]
Please, tell me whether you get f' yet? and DON'T factor, it turns very complicated next in next steps
I understand now that (1-9x)e^{-9x}= f'
Don't factor, please.
\(f'(x) = x'*e^{-9x}+x (e^{-9x})' = e^{-9x} -9xe^{-9x}\) \(f''(x) = (e^{-9x} -9xe^{-9x})'\)
this is why i am so confused.. the factoring part is too much
It's ok when factoring, but why do we make the life harder by product rule again for f" ? now, just take derivative term by term and the second term is exactly what we did for f' * (-9) ,right?
\(f''(x) = (e^{-9x})' -9(xe^{-9x})'\)
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