Question

Will Medal

Answer 1

\[\frac{ \sqrt[3]{6x^2y^4}}{ 2\sqrt[3]{5x^7y} }\]

Answer 2

Divide. Rationalize the denominator. Please show work

Answer 3

@mathmath333 @omarbirjas @pooja195 @PizzaLover123 @Phebe @party_girl @jeffyblood @kdenice123 @Holly00d1248 @hyntc @adamaero @Quan99 @ezrider16 @Burningitdown @King.Void. @KJ4UTS @Librarian @Luigi0210 @logan13 @lsherron @OnePieceFTW @youngnephew34 @Youth @ybarrap @DarkMoonZ @ezrider16 @viixxen @vannah* @JackofallTradez

Answer 4

@jim_thompson5910 @bohotness @YanaSidlinskiy

Answer 5

@SithsAndGiggles @jim_thompson5910

Answer 6

What have you tried?

\[\sqrt[3]{x} \implies x^{1/3}\]

Answer 7

@iambatman Yea, but all i get it an even more complicated answer...Can you take me step by step? I think I may have made a mistake....

Answer 8

@dan815

Answer 9

@jdoe0001

Answer 10

simplifying right?

Answer 11

lemme do as iambatman suggested, let us use rational exponents
one sec

Answer 12

Finally somebody willing to help. I've been at this thing all day.... @jdoe0001

Answer 13

hold the mayo

Answer 14

\(\Large {
\cfrac{ \sqrt[3]{6x^2y^4}}{ 2\sqrt[3]{5x^7y} }\implies \cfrac{ \sqrt[3]{(6x^2y^4)^1}}{ 2\sqrt[3]{(5x^7y)^1} }\implies \cfrac{\left( 6x^2y^4 \right)^{\frac{1}{3}}}{2(5x^7y)^{\frac{1}{3}}}
\\ \quad \\
\cfrac{6^{\frac{1}{3}}x^{2\cdot \frac{1}{3}}y^{4\cdot \frac{1}{3}}}{2(5^{\frac{1}{3}}x^{7\cdot \frac{1}{3}}y^{\frac{1}{3}})}
\implies \cfrac{6^{\frac{1}{3}}x^{\frac{2}{3}}y^{\frac{4}{3}}}{2(5^{\frac{1}{3}}x^{\frac{7}{3}}y^{\frac{1}{3}})}
\\ \quad \\
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
\cfrac{x^{\frac{2}{3}}y^{\frac{4}{3}}}{x^{\frac{7}{3}}y^{\frac{1}{3}}}\implies
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot x^{\frac{2}{3}}y^{\frac{4}{3}}\cdot x^{-\frac{7}{3}}y^{-\frac{1}{3}}
\\ \quad \\

\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
x^{\frac{2}{3}-\frac{7}{3}}y^{\frac{4}{3}-\frac{1}{3}}\implies
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
x^{-\frac{5}{3}}y^{\frac{1}{3}}
\\ \quad \\
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
\cfrac{y^{\frac{1}{3}}}{x^{\frac{5}{3}}}\implies
\cfrac{\sqrt[3]{6}\cdot \sqrt[3]{y}}{2\sqrt[3]{5}\cdot \sqrt[3]{x^5}}\implies
\cfrac{\sqrt[3]{6y}}{2\sqrt[3]{5}\cdot \sqrt[3]{x^3\cdot x^2}}
\\ \quad \\
\cfrac{\sqrt[3]{6y}}{2\sqrt[3]{5}\cdot x\sqrt[3]{x^2}}\implies
\cfrac{\sqrt[3]{6y}}{2x\sqrt[3]{5x^2}}
}\)

Answer 15

Mayo has been held

Answer 16

@jdoe0001 @iambatman , indeed the mayo has been held....

thanks a lot man. life saver.

Answer 17

\(\color{blue}{\text{Originally Posted by}}\) @jdoe0001
\(\Large {
\cfrac{ \sqrt[3]{6x^2y^4}}{ 2\sqrt[3]{5x^7y} }\implies \cfrac{ \sqrt[3]{(6x^2y^4)^1}}{ 2\sqrt[3]{(5x^7y)^1} }\implies \cfrac{\left( 6x^2y^4 \right)^{\frac{1}{3}}}{2(5x^7y)^{\frac{1}{3}}}
\\ \quad \\
\cfrac{6^{\frac{1}{3}}x^{2\cdot \frac{1}{3}}y^{4\cdot \frac{1}{3}}}{2(5^{\frac{1}{3}}x^{7\cdot \frac{1}{3}}y^{\frac{1}{3}})}
\implies \cfrac{6^{\frac{1}{3}}x^{\frac{2}{3}}y^{\frac{4}{3}}}{2(5^{\frac{1}{3}}x^{\frac{7}{3}}y^{\frac{1}{3}})}
\\ \quad \\
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
\cfrac{x^{\frac{2}{3}}y^{\frac{4}{3}}}{x^{\frac{7}{3}}y^{\frac{1}{3}}}\implies
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot x^{\frac{2}{3}}y^{\frac{4}{3}}\cdot x^{-\frac{7}{3}}y^{-\frac{1}{3}}
\\ \quad \\

\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
x^{\frac{2}{3}-\frac{7}{3}}y^{\frac{4}{3}-\frac{1}{3}}\implies
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
x^{-\frac{5}{3}}y^{\frac{1}{3}}
\\ \quad \\
\cfrac{6^{\frac{1}{3}}}{2\cdot 5^{\frac{1}{3}}}\cdot
\cfrac{y^{\frac{1}{3}}}{x^{\frac{5}{3}}}\implies
\cfrac{\sqrt[3]{6}\cdot \sqrt[3]{y}}{2\sqrt[3]{5}\cdot \sqrt[3]{x^5}}\implies
\cfrac{\sqrt[3]{6y}}{2\sqrt[3]{5}\cdot \sqrt[3]{x^3\cdot x^2}}
\\ \quad \\
\cfrac{\sqrt[3]{6y}}{2\sqrt[3]{5}\cdot x\sqrt[3]{x^2}}\implies
\cfrac{\sqrt[3]{6y}}{2x\sqrt[3]{5x^2}}
}\)
\(\color{blue}{\text{End of Quote}}\)
o_o And I thought what I was learning was tough. o_o