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Mathematics 13 Online
OpenStudy (anonymous):

http://prntscr.com/6g0k4b

OpenStudy (anonymous):

@sammixboo @nnesha @pooja195

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

@YanaSidlinskiy

OpenStudy (anonymous):

Well, what would be your first step?

OpenStudy (anonymous):

You want n on its own, you have -np-4, what can you do to move everything but n?

OpenStudy (anonymous):

ok here is what i got -np - 4 <= 2(c - 3) -np - 4 <= 2c - 6 -np - 4 + 4 <= 2c - 6 + 4 -np <= 2c - 10 -np/p <= (2c - 10)/p -n <= (2c - 10)/p but I don't have a negaitive sign. is that because i gotta divide by -p?

OpenStudy (anonymous):

if I do then i got n >= -(2c - 10)/p which is D

OpenStudy (anonymous):

soo it would be D?

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

@Kainui

OpenStudy (jdoe0001):

@KaylaIsBae h mm -6 + 4 = -10?

OpenStudy (jdoe0001):

\(\bf -np-4\le 2(c-3) \\ \quad \\ -np\le 2c-6+4\implies -np\le 2c-2 \\ \quad \\ -n\le \cfrac{2c-2}{p}\impliedby \textit{division by a positive value, no sign change} \\ \quad \\ n{\color{red}{ \ge}}-1\cdot \cfrac{2c-2}{p}\implies n\ge \cfrac{-2c+2}{p}\impliedby \textit{by a negative value, sign change}\)

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