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Mathematics 17 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

He would owe Linda twice the amount he borrowed. He would owe both the same amount of money. He would owe Linda more money. He would owe Drake more money.

OpenStudy (anonymous):

I know for year 30 for Linda he would owe $410, but with drake it is exponential so it will eventually have to owe more, right? so I was thinking D

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

Perhaps. Borrowed money from Linda = $6.18. Borrowed money from Drake = $7. Multiply both of them out, but I think D is the answer.

OpenStudy (anonymous):

Linda = $7 a year Drake = ? it's exponential

OpenStudy (anonymous):

yes, 206 + 6.18 = 212.18, but 212.18 + 6.18 =/= 218.55

OpenStudy (welshfella):

the first one is an arithmetic series with common difference 7 and second is a geometric with common ratio 1.03

OpenStudy (anonymous):

so he would owe drake around $500 since 206(1.03)^30 = 500.02

OpenStudy (anonymous):

206(1.03)^1 = 212.18 206(1.03)^2 = 218.5454 206(1.03)^3 = 225.102 .....

OpenStudy (anonymous):

so it would be D

OpenStudy (anonymous):

Sorry, derp moment. xD I forgot to calculate the rest of the years given, but yeah, it is exponential.

OpenStudy (welshfella):

yes its definitely D

OpenStudy (anonymous):

thanks! i was confused. this is a practise exam for my end-of-segment test and I wanna make sure I got everything down before taking the big test

OpenStudy (anonymous):

did you get 1.03 by dividing two y values?

OpenStudy (anonymous):

for drake @welshfella

OpenStudy (welshfella):

yes - its approximately 1.03

OpenStudy (welshfella):

2nd/ist 3rd/2nd and 4th/3rd are very close to 1.03

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