Question

Find the general solution to y*dy/dx=4^x

Answer 1

Ok, so we have
$$
y \cdot \frac{dy}{dx} = 4^x \\
y \cdot dy = 4^x \cdot dx \\
\int y \cdot dy = \int 4^x \cdot dx\\
\frac{y^2}{2} = \frac{4^x}{\ln(4)} + C \\
y^2 = \frac{2 \cdot 4^x}{\ln(4)} + C \\
y = \pm\sqrt{\frac{2 \cdot 4^x}{\ln(4)} + C}
$$

Answer 2

Thanks, I'm embarrassed I couldn't get this. I was just confused as to why Microsoft Math wasn't giving me that answer, but I think it's an issue with the program.

Answer 3

Lol don't worry that's ok =)
You can use wolfram alpha for this
http://www.wolframalpha.com/input/?i=y*dy%2Fdx%3D4%5Ex