Question

f(x)=cos(x) and g(x)=(x^(6))+1. Find: (g(f(x)))'

I got 6x^5(cos(x))(-sin(x)) but is wrong.....where am I mistaken?
Thanks

Answer 1

using chain rule

Answer 2

\[[g(f(x))]'=g'(f(x))f'(x)\]

Answer 3

so.....6x^5(cos(x)(-sin(x))....?

Answer 4

no

Answer 5

\[g'(x)=6x^5\]
\[g'(f(x))=6(\cos(x))^5\]

Answer 6

6(cos(x))^5(-sin(x))

Answer 7

yes

Answer 8

thank you very much.......I appreciate your time

Answer 9

np