Scoring a hole-in-one is the greatest shot a golfer can make. Once 8 professional golfers each made holes-in-one on the 6th hole at the same golf course at the same tournament. It has been found that the estimated probability of making a hole-in-one is 1/2153for male professionals. Suppose that a sample of 8 professional male golfers is randomly selected.

What is the probability that at least one of these golfers makes a hole-in-one on the 15th hole at the same tournament?

Question

Scoring a hole-in-one is the greatest shot a golfer can make. Once 8 professional golfers each made holes-in-one on the 6th hole at the same golf course at the same tournament. It has been found that the estimated probability of making a hole-in-one is 1/2153for male professionals. Suppose that a sample of 8 professional male golfers is randomly selected.

What is the probability that at least one of these golfers makes a hole-in-one on the 15th hole at the same tournament?

anonymous · Answer

@sammixboo

sammixboo · Answer

Ugh I hate probability give me a sec to try to figure this out.

sammixboo · Answer

Sorry, can't help. I forgot how to do this

anonymous · Answer

It's fine thank you for trying !!

kropot72 · Answer

Let the probability that none of the eight players makes a hole-in-one be P(0).
Then the probability that at least one of these golfers makes a hole-in-one on the 15th hole at the same tournament is given by:
1.0000 - P(0)
$$\large P(0)=(\frac{2152}{2153})^{8}$$
Therefore
$$\large P(none\ make\ a\ holeinone)=1.0000-(\frac{2152}{2153})^{8}=you\ can\ calculate$$