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Find f'(x) if f(x)= ∫ 0 to x^(2) (sqrt(1+r^(3)))
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General formula derivative of integration\( \Large \dfrac{d}{dx}\int \limits_{f(x)}^{g(x)}h(x)dx = h(g(x))g'(x)-h(f(x))f'(x)\)
in your case, g(x) = x^2 f(x) = 0 h(x) = \(\sqrt{1+r^3}\)
f(x) = 0, so just \(\Large h(g(x))g'(x)\)
try now :)
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welcome ^_^
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