it will be undefined when
\(\large \color{black}{\begin{align} \frac{ 3v^2+9 }{ v^2-2v-3 }=\infty\hspace{.33em}\\~\\
\frac{ 3v^2+9 }{ v^2-2v-3 }=\dfrac{1}{0}\hspace{.33em}\\~\\
\frac{ v^2-2v-3 }{ 3v^2+9 }=\dfrac{0}{1}\hspace{.33em}\\~\\
v^2-2v-3 =0
\end{align}}\)
solve the quadratic equation now
OpenStudy (anonymous):
unidentified. means v^2-2v-3=0
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OpenStudy (anonymous):
solve for v
OpenStudy (anonymous):
what would that value of v be when it is unidentified is what the computer is asking for
OpenStudy (anonymous):
oh so i solve for v and that is the answer?
OpenStudy (anonymous):
yes
OpenStudy (mathmath333):
make sure the spelling is correct whether it is undefined or unidentified.
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OpenStudy (anonymous):
-1 and 3
OpenStudy (anonymous):
is that correct?
OpenStudy (anonymous):
@AJ01 ?
OpenStudy (anonymous):
he is offline. does anyone else know?
OpenStudy (shamim):
v2-2v-3=0
v^2-3v+v-3=0
v(v-3)+1(v-3)=0
(v+1)(v-3)=0
So
v=-1,3
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