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Complex number question
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The complex number \[zi = \frac{ a }{ 1+i } \] and \[z2=\frac{ b }{ 1+2i}\] where a and b are real are such that zi+z2= 1 . Find a and b
it is like you would with surds, you want a real number on the bottom so for example \[z _{1}= \frac{ a (1-i)}{ (1+i)(1-i) }\] \[z_{2}= \frac{b(1-2i)}{ (1+2i)(1-2i) }\]
then you know how to add fractions of real numbers, then you just add the fractions and solve for a and b since you know it will equal 1 you will compare the real and imaginary parts
Thanks dozennss !!
need me to check your answer or are you okay?
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Its totally fine :) have the final answers and got them right :)
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