Write the standard form of the line that passes through the given points. (4, 7) and (0, 7)
@Kommander_Kitten
This should help: http://www.algebra.com/algebra/homework/equations/Equations.faq.question.201391.html
This is a horizontal line, so the slope is 0.
to work out the equation of a line, we will start by finding the gradient of the line also known as the slope \[m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\] where \[(4,7)=(x _{1},y _{1})\] and \[(0,7)=(x _{2},y _{2})\] now the standard equation of a line \[y-y _{1}=m(x-x _{1})\]
0? Alright, thank you. How would I write it in standard form though? That's what I cannot figure out.
Plug in what you know: y-7=0(x-4)
I suck at standard form
Simplify, and get it into standard form.
standard form is y=mx+c where m is the slope and c is the intercept
That's not standard form. y=mx+b is slope-intercept form.
lol i remember now, you are the person who doesn't want me to help you sorry
Lol it's not that. I've been b*tchy these past few days to everybody. I'm sorry for that
oh it is fine lol, but both are the slope intercept form, it just depends what book or teacher you get, some use y=mx+a good luck with your other questions
I do online school so I have to teach myself -_- Lol I wish they gave me books. I just have the Internet
I don't understand how to get it into that form though. I have it all wrote down, like all my work. It's just not clicking in my head lol
yeah self teaching is hard anyways to finish off your question use \[y-y _{1}=m(x-x _{1})\] substitute your values in where (4,7)=(x1,y1) so you get y-7=0(x-4) y-7=0 y=7
Write it in slope-intercept form, and then change it to standard form= y=0x+7----->y+0x=7
The standard form and answer is y+0x=7
THAT'S WHAT I HAD! It just didn't look right to me lol
I wish I could give you both a medal!
give credit to him
he deserved it
Okay. But thank you, too, @amorfide !
anytime just tag me whenever you need help
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