Write the standard form of the line that contains a slope of 2/3 and passes through the point (1, 1).
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Nnesha (nnesha):
\[\huge\rm y = mx + b \] slope intercept form
where m is slope
and b is y-intercept so replace m by 2/3
and x and y by (1,1)
then solve for b
OpenStudy (anonymous):
How?
Nnesha (nnesha):
first replace m and x y values and let me know what you get after that
Nnesha (nnesha):
by**
OpenStudy (anonymous):
actually you can use the slope intercept form:
y - y0 = m(x-x0)
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OpenStudy (anonymous):
where the coordinates are (x0, y0) and the slope is m
Nnesha (nnesha):
^^that one is point slope form :)
OpenStudy (anonymous):
@Kommander_Kitten
OpenStudy (anonymous):
@AlexandervonHumboldt2
Nnesha (nnesha):
replace m by 2/3
x by 1
y by 1
in order pair first number is x and 2nd one is y \[\huge\rm (x ,y )\]
do it and show ur work
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OpenStudy (anonymous):
I don't understand
Nnesha (nnesha):
what you don't understand ?
OpenStudy (anonymous):
What I'm supposed to do
Nnesha (nnesha):
you suppose to replace m by 2/3
x by 1
and y by 1
into this equation y=mx + b
OpenStudy (anonymous):
But it's supposed to be in standard form, not slope-intercept
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Nnesha (nnesha):
ik first you have to solve for b(y-intercept)
OpenStudy (anonymous):
Okay so 1=2/3(1)+b
Nnesha (nnesha):
yes solve for b
OpenStudy (anonymous):
How..lol
OpenStudy (anonymous):
b=1/3
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Nnesha (nnesha):
yes right
OpenStudy (anonymous):
So now what?
Nnesha (nnesha):
standard form is
Ax +By = C
OpenStudy (anonymous):
OMG I feel like such a blonde now -_- lol
OpenStudy (anonymous):
2/3x+1/3y=1 ..?
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Nnesha (nnesha):
the equation u just got is y = 2/3x + 1/3
right both have same denominator so we can take it common \[\frac{ 2 }{ 3 }x +\frac{ 1 }{ 3 } = \frac{ 2x +1 }{ 3 }\] so we can wirte like this
Nnesha (nnesha):
write*
Nnesha (nnesha):
\[\huge\rm y = \frac{ 2x +1 }{ 3 }\]
multiply both side by 3
OpenStudy (anonymous):
6x+6/9 ?
Nnesha (nnesha):
nope
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