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Mathematics 20 Online
OpenStudy (anonymous):

NEED URGENT HELP!

OpenStudy (anonymous):

Samuel is 1/2 as old as his brother. In seven years, he will be 2/3 as old as his brother will be. Find their present ages. Show each step of your work.

OpenStudy (jhannybean):

Make a set of linear equations, one for sam's age and one for their ages together after 17 years.

OpenStudy (anonymous):

i dont get it...

OpenStudy (anonymous):

Let x = samuel's age y = his brothers In 7 years samuel will be x+7, and his brother will be y+7, you can let samuel be x=1/2y I think you can finish it off from here.

OpenStudy (anonymous):

Notice in 7 years he will be 2/3 as old as his brother, so set the equations up now.

OpenStudy (jhannybean):

Sam = x brother = y x=\(\frac{1}{2}\)y 17 years later, both their ages increase. x+17 = \(\frac{2}{3}\)(y+17)

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

Oh, ok I understand now

OpenStudy (jhannybean):

Well crap I was typing it out but had my variables mixed up. Key component `sam will be 2/3 as old as his brother`

OpenStudy (anonymous):

Where do you keep getting 17 years

OpenStudy (jhannybean):

Oh hahahaha

OpenStudy (anonymous):

hahaha

OpenStudy (jhannybean):

I meant 7 :<

OpenStudy (anonymous):

its ok

OpenStudy (anonymous):

so just plug in 7 instead of 17, then it will be the same, or did everything just blow in our face @Jhannybean

OpenStudy (anonymous):

Yeah just change 17 to 7

OpenStudy (jhannybean):

What he said.

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