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Mathematics 22 Online
OpenStudy (anonymous):

What is the length of stack E C with bar on top in the rectangular prism? Round to the nearest tenth of a centimeter. A. 7.5 cm B. 9.4 cm C. 12.6 cm D. 15.3 cm

OpenStudy (anonymous):

OpenStudy (anonymous):

@Michele_Laino i got d

OpenStudy (michele_laino):

we have to compute this: \[EC = \sqrt {E{G^2} + C{G^2}} = \sqrt {\left( {{8^2} + {5^2}} \right) + {{12}^2}} = ...?\] since: \[E{G^2} = {8^2} + {5^2}\]

OpenStudy (anonymous):

9.4

OpenStudy (anonymous):

oh wait that is what i got

OpenStudy (anonymous):

is that right

OpenStudy (michele_laino):

no, since you wrote EG, whereas we want to know what is EC

OpenStudy (anonymous):

oh

OpenStudy (michele_laino):

hint: \[EC = \sqrt {E{G^2} + C{G^2}} = \sqrt {\left( {{8^2} + {5^2}} \right) + {{12}^2}} = \sqrt {64 + 25 + 144} = ...?\]

OpenStudy (anonymous):

ohhh

OpenStudy (anonymous):

okay so before i got 232.36... but now i got 15.26 so it is 15.3

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

yayy

OpenStudy (anonymous):

i have one more can you help

OpenStudy (michele_laino):

ok!

OpenStudy (anonymous):

(3 pt) What is the area of the rectangle? Round to the nearest square inch. A. 114 in2 B. 108 in2 C. 106 in2 D. 102 in2

OpenStudy (anonymous):

OpenStudy (anonymous):

i got d

OpenStudy (anonymous):

@MCLover1477

OpenStudy (michele_laino):

we have: \[AB = \sqrt {B{D^2} - A{D^2}} = \sqrt {{{18}^2} - {6^2}} = ...?\]

OpenStudy (michele_laino):

we have to compute that first

OpenStudy (anonymous):

288 then squared is 17

OpenStudy (anonymous):

then 17 times 6 is 102

OpenStudy (anonymous):

because area of rectangle= bh

OpenStudy (michele_laino):

wait, we have a triangle, so the area is: (17*6)/2=...?

OpenStudy (michele_laino):

sorry we have a rectangle, so you are right!

OpenStudy (anonymous):

one more

OpenStudy (michele_laino):

area is 102 in^2

OpenStudy (michele_laino):

ok! I'm ready!

OpenStudy (anonymous):

sorry i cant help right now im a little busy sorry

OpenStudy (anonymous):

What is the area of the equilateral triangle? Round to the nearest square centimeter. cm2 Equilateral triangle A B C with side length of eight centimeters

OpenStudy (anonymous):

you dont need the pic. each side is 8

OpenStudy (michele_laino):

do you know the Heron's formula?

OpenStudy (anonymous):

no

OpenStudy (michele_laino):

if not, look at this drawing: |dw:1426284316542:dw|

OpenStudy (michele_laino):

we have to compute this, first: \[CH = \sqrt {B{C^2} - B{H^2}} = \sqrt {{8^2} - {4^2}} = ...?\]

OpenStudy (anonymous):

6.9

OpenStudy (anonymous):

or 7

OpenStudy (michele_laino):

it is 7

OpenStudy (anonymous):

okay now what

OpenStudy (michele_laino):

so, the area is: \[{\text{Area = }}\frac{{{\text{base }} \times {\text{ height}}}}{2} = \frac{{8 \times 6.9}}{2} = ...?\]

OpenStudy (michele_laino):

or: \[{\text{Area = }}\frac{{{\text{base }} \times {\text{ height}}}}{2} = \frac{{8 \times 7}}{2} = ...?\]

OpenStudy (michele_laino):

we can use 7 in place of 6.9

OpenStudy (michele_laino):

So, what do you get?

OpenStudy (anonymous):

28

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

thanks so much

OpenStudy (michele_laino):

thank you!

OpenStudy (anonymous):

ill definitley come to you when i need help!!

OpenStudy (michele_laino):

ok!

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