What is the slope-intercept form of the function described by this table? x 1 2 3 4 y 1 −2 −5 −8 y = _ x +_
@dagrothus
@iambatman
@dagrothus
@Legends
@AlexandervonHumboldt2
@Jhannybean
@peterg2001
plz help
sorry cant help @AlexandervonHumboldt2 @EclipsedStar
@EclipsedStar
@AlexandervonHumboldt2
@matt101
thx @matt101
You need to solve this in two steps. First find the slope (first blank), then find the y-intercept (second blank). To find the slope, choose any two points from the ones you gave. To find the slope: \[Slope = {x_2-x_1 \over y_2-y_1}\] For the y-intercept: Once you have the slope, choose any one point from the ones you gave, and solve for the y-intercept by subbing in the slope and the x and y values from that point! Let me know what you get!
-3
i thought it was y2-y1/x2-x1. lol
That's the right slope! Sorry, I just realized I reversed the x's and y's in the slope equation. It's rise/run, so it should read: \[Slope={y_2-y_1 \over x_2-x_1}\] Now that you have the slope, you can use it and another point to find the y-intercept.
ohh.
Yeah I just noticed my mistake - you're absolutely right.
which point?
which point?
If we call slope m, your equation becomes y = mx + ? We're trying to solve for the ? which is the y-intercept. We have m, and we can take the x and y from any point on the line. Use that to find ?
It can be any of the points you listed above, it won't change your answer!
-2-1?
would the other answer be 1? @matt101
nv i got it thx
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