The graph of f(x) consists of two straight lines and a semicircle. Use this graph to evaluate (to three decimal places).
28.283 12.000 14.000 34.566 20.283
@iambatman
@Jhannybean
@sammixboo
\[\int_0^2 f(x)dx+\int_2^4f(x)dx\]
I could solve this if I knew what f(x) was.
@Jhannybean
Exactly, I don't know what f(x) is either.
How do I find that out. Or do I not need to?
Butyou could figure it out considering you have a slope and a y intercept (b=0)
the integral is just the area under the curve. You want the integral from 0 to 4 so you can cut that picture any way you want to make the geometry easier. I would break it into a triangle on the left from 0 to 2, the area of which would be 2*6/2 = 6 units. Then break the integral from 2 to 4 into a triangle on top of a square. The square has an area of 2*2 = 4 units. The triangle above it has an area of 4*2/2 = 4 units as well. So the total area will be 6+4+4 = 14.000 units, so the answer is C
that, OR I suppose you could find the equations of each line and take 2 separate integrals, but there's no need to overcomplicate it
Alright thank you. Also, what would the answer be if it was integral (2,6) instead?
15.142 22.283 12.785 28.283 18.283
Use the same method.
What is the area of a semi circle?
a
A = (pi * r ^ 2) / 2
the format on this site's a bit weird, it wont let me post my explanation
but yeah same thing basically
So the answer is 15.142?
yeah
make sure you understand how to do that
Alright thanks! Also I have one more question, do you think you have time to try it out?
what is it?
From the definition of the definite integral, we have:
You already asked this and @iambatman explained it to you.
Answers:
Yes I know, but I want a second opinion.
Have you tried working it out using his explanation?
@dagrothus
Does this make any sense to you?
yeah i looked at his explanation, he pretty much gives you the answer, just try to understand what he wrote
look back at the definition of an integral
Well I think the answer might be the second one. Is that correct?
ya i think so, but I haven't done this stuff in a while
Alright thank you!
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