Suppose a triangle has sides a, b, and c, and that a^2 + b^2

Question

Suppose a triangle has sides a, b, and c, and that a^2 + b^2 < c^2. Let (theta) be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply.

Please explain. Thank you!

kj4uts · Answer

attachment

freckles · Answer

hint:
so we know we don't have a right triangle ...
by law of cosines we have:
hmmm we are given that
$$0=a^2+b^2-c^2-2ab \cos(\theta) <c^2-c^2-2abcos(\theta)=-2abcos(\theta) \ 0 < -2 ab \cos(\theta) \ \text{ multiplying the negative 1 on both sides gives } 0>2 ab \cos(\theta)$$

freckles · Answer

oops I gave one answer :p
and kinda gave the other