Show that the two functions grow at the same rate: sqrt(9^x + 2^x) and 3^x
I've tried a ton to manipulate the limit, but I just can't get it to turn into a constant that isn't 0
I tried squaring the part inside of the limit, but that didn't help all that much
oh nvm
This may or may not use l'hopital btw
yeah you can use l'hopital's rule to find that the\[\lim_{x \rightarrow \infty}(\sqrt{9^x+2^x)}/(3^x)) = 1\] If you just plug in infinity for x you'll get infinity/infinity which is undefined, so you have to use l'hopital's rule ( differentiate the top and bottom until you dont get infinity/infinity)
Except that by using l'Hopital, it overcomplicates the problem a tremendous amount
You get all of these nasty natural logs in there, in addition to the regular exponential functions that are already in the problem, so it only makes the problem worse
@e.mccormick If you can help me that would be greatly appreciated
No matter what I did, I just could not get that to simplify inside of the limit :/
you don't need to use L'Hospitals rule
Yeah, I kinda figured because it wasn't going to help at all
put the \(3^x\) under the square root
Ok, so that would make it 3^2x right?
you can write it another way
How?
functions grow at the same rate if \[\lim_{x \rightarrow \infty} \frac{ f(x) }{g(x) } = M \neq 0\] where M is a finite non zero number
Yes
I need the limit to check out to a non-zero constant
I cheated but there you go
There was some black magic in that solution
you can also write it as \[\frac{\sqrt{9^x+2^x}}{3^x}=\sqrt{\frac{9^x+2^x}{9^x}}=\sqrt{1+\left(\frac{2}{9}\right)^x}\]
where was the black magic lmao
Whooooa
Oh my god
Can you just pull down the 2 from the exponent like that to square the 3?
I feel like wafflemans brain just got blown
Because that is some crazy stuff right there
I just became a toasted waffle
\[(3^x)^2=3^{2x}=(3^2)^x=9^x\]
Mind blown level=Hiroshima
basically he is saying \[\sqrt{9^{x}} = 3^{x}\]
yeah what zarkon said lol
That is crazy. Thanks guys. I never would have even considered doing that.
I tried to simplify myself and gave up because I never would have gotta that stuff either tbh sucks to be you
Hahaha. BC calc IS pretty miserable at times
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