If the length of a rectangle is increased by a factor of 5/2 and the width is decreased by a factor of 1/2, by what factor does the area change? A. look at the picture B. 2 C. 3 D. 10
please help, ill give medals
multiply the fractions because A=LW where A is area L is length W is width if you have a 2x3 rectangle area is 2x3=6 if you change the length by a factor of 1/2 and the width by a factor of 5/2 you get \[A=\frac{ 5 }{2? } \frac{ 1 }{ 2 } LW\]
so just multiply your fractions to get the factor that the area changes
tysm, can you help me with one more please?
i can try
Triangle ABC is similar to triangle DEF If the area of Triangle DEF is 567cm^2, what ratio would you multiply 567 by to find the area of Triangle ABC
do you have a picture?
you know the hypotenuse on the first triangle is 100 the second triangle the hypotenuse is 75 75/100 is 3/4 so your factor that the triangle has changed by is 3/4 work out the sides of the second triangle by doing 60x3/4 and 80x3/4 then use the formula to work out the area of a triangle A=0.5(bxh) to get 0.5(45x60) divide this by the area of the first triangle and you will get a ratio which is 9/16 so the factor which changed the size of the triangle is 3/4 our answer is 9/16 therefore to figure out the factor the area changes is the size factor squared so 9/16 is your answer
9/16 isn't an answer choice
a.4/9 b.8/9 c.16/9 d.48/9
@amorfide
then i dont know because I worked it out to be 9/16
ok thanks
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