Consider the function. Use the notion of signed area to evaluate the following definite integral (-4,4) f(x) dx.
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OpenStudy (nathanjhw):
OpenStudy (nathanjhw):
OpenStudy (nathanjhw):
2 – 2 pi
4 – pi
2 – 4 pi
4 – 4 pi
4 – 2 pi
OpenStudy (nathanjhw):
@Zarkon
OpenStudy (nathanjhw):
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
how far did you get into this?
OpenStudy (nathanjhw):
I'm not sure where to start.
jimthompson5910 (jim_thompson5910):
why not break it up into 3 pieces and find the area of each piece
jimthompson5910 (jim_thompson5910):
like so
OpenStudy (nathanjhw):
-x-2=-16
-sqrt(4-x^2) = -6.283 - 8.588i
x-2 = -16
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jimthompson5910 (jim_thompson5910):
idk how you're getting that
OpenStudy (nathanjhw):
Im taking the integral of (-4,4) and filling in those values for f(x).
jimthompson5910 (jim_thompson5910):
i see
jimthompson5910 (jim_thompson5910):
break it up into 3 pieces
jimthompson5910 (jim_thompson5910):
first piece
\[\Large \int_{-4}^{-2}(-x-2)dx\]
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jimthompson5910 (jim_thompson5910):
second piece
\[\Large \int_{-2}^{0}-\sqrt{4-x^2}dx\]
OpenStudy (nathanjhw):
-10
jimthompson5910 (jim_thompson5910):
third piece
\[\Large \int_{2}^{4}(x-2)dx\]
jimthompson5910 (jim_thompson5910):
evaluate each integral
OpenStudy (nathanjhw):
-10
-pi
2
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jimthompson5910 (jim_thompson5910):
exactly one of those that you listed is incorrect (the other two are correct)
OpenStudy (nathanjhw):
The first one is -2. Forgot the -x.
jimthompson5910 (jim_thompson5910):
hint:
areas above the x axis are positive areas
areas below the x axis are negative areas
you can simply look and determine the sign of the area without having to do any math at all
OpenStudy (nathanjhw):
So is the answer: 2-2pi?
OpenStudy (nathanjhw):
Or am I jumping to conclusions?
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jimthompson5910 (jim_thompson5910):
list the areas of each piece again
OpenStudy (nathanjhw):
-2
-pi
2
jimthompson5910 (jim_thompson5910):
the -2 is incorrect
why? because the red triangle is ABOVE the x axis, so it has to be positive at least. It's some positive number. Try again
OpenStudy (nathanjhw):
2
-pi
2
jimthompson5910 (jim_thompson5910):
yep, now we add:
(Area1)+(Area2)+(Area3) = (2) + (-pi) + (2) = 4 - pi
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OpenStudy (nathanjhw):
Thanks. I was just making small mistakes, but I think I understand it now.
OpenStudy (nathanjhw):
Are you able to help me through another one?
jimthompson5910 (jim_thompson5910):
sure, just one more though
OpenStudy (nathanjhw):
Alright thanks! I think I mainly need help breaking it into pieces.
OpenStudy (nathanjhw):
The following graph of f(x) consists of line segments and semicircles. Use the graph and the notion of signed area to evaluate the definite integral (1,9) f(x) dx.
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OpenStudy (nathanjhw):
OpenStudy (nathanjhw):
18 – 4pi
16 – 2.5pi
16 – 2pi
14 – pi
14 – 4pi
jimthompson5910 (jim_thompson5910):
break it up like this
jimthompson5910 (jim_thompson5910):
actually, you don't need one line in there, here's a more simpler version
OpenStudy (nathanjhw):
Now how do I find the integrals of all those pieces?
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jimthompson5910 (jim_thompson5910):
well you can use plain old geometry instead of calculus to find the area of each piece
OpenStudy (nathanjhw):
So I think the first piece's area is pi/2= 1.57
OpenStudy (nathanjhw):
I used the area of a semicircle which is (pi x r^2)/2.(pi x 1^2)/2 =pi/2
OpenStudy (nathanjhw):
I then broke the second piece into two and made a square and a triangle.
OpenStudy (nathanjhw):
The area of the square is 4.
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OpenStudy (nathanjhw):
The area of the triangle is (4 x 2)/2=4
OpenStudy (nathanjhw):
So the area of the whole second piece is 8.
OpenStudy (nathanjhw):
The area of the third piece is (6x2)/2 = 6
OpenStudy (nathanjhw):
The area of the last piece is (pi x 3^2)/2 = (pi x 9)/2 = 14.13
OpenStudy (nathanjhw):
All together the area of all the pieces is 1.57 + 8 + 6 + 14.13 = 29.7
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jimthompson5910 (jim_thompson5910):
one sec
jimthompson5910 (jim_thompson5910):
you forgot about the 2x2 square that is below the first semicircle
OpenStudy (nathanjhw):
So then it's 33.7?
OpenStudy (nathanjhw):
Wait I need to minus the last semicircle.
OpenStudy (nathanjhw):
So i get 5.44.
1.57 + 4 + 8 +6+ + (-14.13).
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OpenStudy (nathanjhw):
I don't think that is one of my answers @jim_thompson5910
OpenStudy (nathanjhw):
Did I do something wrong?
jimthompson5910 (jim_thompson5910):
let me see
jimthompson5910 (jim_thompson5910):
ok, two things
1) keep everything in terms of pi (don't approximate pi)
2) the semicircle under the curve has a negative area
OpenStudy (nathanjhw):
So the first semicircle is pi/2 and the second semicircle is -9pi/2. I think everything else should be the same.
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OpenStudy (nathanjhw):
Should I multiple all the values by 2?
jimthompson5910 (jim_thompson5910):
why multiply by 2?
OpenStudy (nathanjhw):
So I get pi and -9pi.
OpenStudy (nathanjhw):
I'd get 36 -8pi = 4-2pi.
OpenStudy (nathanjhw):
or 18 - 4pi. Which is one of my answers.
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OpenStudy (nathanjhw):
Yeah I think that's right.
OpenStudy (nathanjhw):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
18-4pi is correct
OpenStudy (nathanjhw):
Alright I have one more. I'm almost possible I know the answer, but do you mind if I just double check with you?
OpenStudy (nathanjhw):
It's pretty basic.
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OpenStudy (nathanjhw):
The graph of f(x) is shown below. Which of the following are true?
OpenStudy (nathanjhw):
I only.
II only.
III only.
II and III only.
I and II only. <---- My answer
jimthompson5910 (jim_thompson5910):
one sec
jimthompson5910 (jim_thompson5910):
I agree with what you got. Nice job
OpenStudy (nathanjhw):
Thank you very much! I really appreciate you spending all this time helping me. I'd give you more medals if I could, but I can't. At the very least you have a fan.
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