eric leans a ladder against the roof of his house so that the ladder forms a 70 degree angle with the ground. the roof of the house is 13 feet above the ground. how far is the bottom of the ladder from the base of the house? round the answer to the nearest tenth. a. 0.2 feet b. 4.4 feet c. 4.7 feet d. 71.2 feet
@pitamar
ANYONE PLLZZZ HELP!!!
|dw:1426293077304:dw|
hmm, forgot to draw 90 degrees angle there |dw:1426293150032:dw| Can you tell me what will be the \(\frac{13}{x}\) in the triangle? what trig function can you use to get this ratio?
not sure
ok, if we have a right angle triangle: |dw:1426293340228:dw| with angle alpha (\(\alpha\)), sides a,b and hypotenuse c. Then \(\frac{a}{c} = \sin(\alpha)\) \(\frac{b}{c} = \cos(\alpha)\) \(\frac{a}{b} = \tan(\alpha)\)
which one is like what we have here?
sin
no, because 13 in our case is like \(a\) in the drawing and \(x\) in our case is like \(b\) in the drawing So \( \frac{13}{x} = \frac{a}{b} = ?\)
is 70 a or is 70 b??
70 is alpha (\(\alpha\)) the angle
13 divided by 70??
no. let me show you what I mean. We want to know that \(\frac{13}{x}\) is. we look at the drawing and see: 13 is the side in front of the angle 70. x is the side adjacent to the angle 70. That is just like \(\frac{a}{b}\) which I know that is \( \tan(\alpha\)). In my case \(a = 13_{ft} \qquad b=x \qquad \alpha = 70^\circ\) so I get: $$ \frac{a}{b} = \tan(\alpha) \implies \frac{13_{ft}}{x} = \tan(70^\circ) $$ Ok so far?
yeaa
i think so
Ok, but we know what \(\tan(70^\circ)\) is. we go to a calculator and type it: http://www.wolframalpha.com/input/?i=tan%2870+degrees%29 Which is about 2.74 So we say: $$ \frac{13_{ft}}{x} = 2.74 $$Can you find x?
36.52?
well let's see. to solve x we have to multiply both sides by x and divide by 2.74: $$ \frac{13_{ft}}{x} = 2.74 \implies 13_{ft} = 2.74 \cdot x \implies x = \frac{13_{ft}}{2.74} $$what is 13/2.74?
4.7 so its c right???!!!
yep
ty!!
one more
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