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Mathematics 7 Online
OpenStudy (anonymous):

Kindly help with probability based on integrals. Photo is attached. I am kind of confused as to part a and b. For part a, I've set my lower limit to 1 and upper limit to infinity but the result is ~20 which exceeds 1.

OpenStudy (anonymous):

OpenStudy (ybarrap):

For a) $$ \text{f(x)=0},\text{for }1<X\le4 $$ Do you see that?

OpenStudy (anonymous):

yes, are you not taking zero into consideration or it does not really have an effect?

OpenStudy (ybarrap):

1 < X is the same as X >1, so zero is not part of the question for this part

OpenStudy (ybarrap):

Do you see that?

OpenStudy (anonymous):

i see that

OpenStudy (ybarrap):

So any X < 4 is zero, so we should focus only on those values of X > 4. Any X < 4 is zero

OpenStudy (ybarrap):

I should say, for any x < 4, f(x) = 0

OpenStudy (anonymous):

that's much better.

OpenStudy (ybarrap):

We are given that for X>4 $$ f(x)=e^{-(x-4)} $$ Which means that for X > 1 (which is what a) is asking us), we only care about X > 4, since $$ \text{f(x)=0},\text{for }1<X\le4 $$

OpenStudy (anonymous):

therefore my limit goes from 4 to infinity.

OpenStudy (ybarrap):

yes!!

OpenStudy (anonymous):

turn gives me a probability of 1. this will be true since 1 is less than x.

OpenStudy (ybarrap):

yes, this is a pdf, integrating across its entire domain, so the integral will equal to 1

OpenStudy (anonymous):

then for part b i just go from 4 to 5.

OpenStudy (ybarrap):

perfect!

OpenStudy (anonymous):

thanks, i needed the understanding. crunching numbers is easy.

OpenStudy (ybarrap):

You're welcome

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