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OpenStudy (anonymous):
given that the horizontal distance from the hoop to the free throw line (at point a) is 15 feet, how tall is the hoop? round the answer to the nearest whole foot
11 years ago
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OpenStudy (anonymous):
11 years ago
OpenStudy (anonymous):
@pitamar
11 years ago
OpenStudy (ybarrap):
|dw:1426296590651:dw|
$$
\tan^{-1}{h\over15}=33.69\\
h=15\times \tan33.69
$$
11 years ago
OpenStudy (anonymous):
505? thats wat igot
11 years ago
OpenStudy (anonymous):
lol I hope sure baskets are not 505 feet high hehe
What is tan33.69?
11 years ago
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OpenStudy (anonymous):
idont even know lol
11 years ago
OpenStudy (anonymous):
you're not supposed to, use a calculator =)
and make sure you work in degrees and not radians
11 years ago
OpenStudy (anonymous):
do i dive 505 and 33.69??
11 years ago
OpenStudy (anonymous):
leave the 505, i'm not sure how you got that
use a calculator and first calculate \(\tan(33.69^\circ)\)
11 years ago
OpenStudy (anonymous):
i got 0.666
11 years ago
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OpenStudy (anonymous):
good. now we know \(h = 15 \cdot \tan(33.69^\circ)\)
so take that 0.666 and multiply by 15. what do you get?
11 years ago
OpenStudy (anonymous):
is it 9.9?
11 years ago
OpenStudy (anonymous):
so it has to be c right?? rounding to 10
11 years ago
OpenStudy (anonymous):
yes. right =)
11 years ago
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OpenStudy (anonymous):
ty so much !!! hope i see u later again !!!!
11 years ago
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