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Mathematics 10 Online
OpenStudy (anonymous):

given that the horizontal distance from the hoop to the free throw line (at point a) is 15 feet, how tall is the hoop? round the answer to the nearest whole foot

OpenStudy (anonymous):

OpenStudy (anonymous):

@pitamar

OpenStudy (ybarrap):

|dw:1426296590651:dw| $$ \tan^{-1}{h\over15}=33.69\\ h=15\times \tan33.69 $$

OpenStudy (anonymous):

505? thats wat igot

OpenStudy (anonymous):

lol I hope sure baskets are not 505 feet high hehe What is tan33.69?

OpenStudy (anonymous):

idont even know lol

OpenStudy (anonymous):

you're not supposed to, use a calculator =) and make sure you work in degrees and not radians

OpenStudy (anonymous):

do i dive 505 and 33.69??

OpenStudy (anonymous):

leave the 505, i'm not sure how you got that use a calculator and first calculate \(\tan(33.69^\circ)\)

OpenStudy (anonymous):

i got 0.666

OpenStudy (anonymous):

good. now we know \(h = 15 \cdot \tan(33.69^\circ)\) so take that 0.666 and multiply by 15. what do you get?

OpenStudy (anonymous):

is it 9.9?

OpenStudy (anonymous):

so it has to be c right?? rounding to 10

OpenStudy (anonymous):

well it's closer to 10: http://www.wolframalpha.com/input/?i=tan%2833.69+degrees%29*15

OpenStudy (anonymous):

yes. right =)

OpenStudy (anonymous):

ty so much !!! hope i see u later again !!!!

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