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Physics 20 Online
OpenStudy (anonymous):

Please Help - medal for help - A bus travels at 25 m/s then decelerate steadily.It comes to a complete stop in 40 seconds.What is it's acceleration ? Not sure how to find answer , can you explain it to me TY !

OpenStudy (matt101):

The question gives us the initial velocity, v(i), of the bus, as well as the time, t, it takes for the bus to come to a stop. The equation for acceleration is: \[a={v_f-v_i \over t}\] We have v(i) and t. The trouble is we can only solve for a if we have the final velocity, v(f), as well. The question actually does give us v(f) - remember, the bus came to a complete stop, so its final velocity must be 0 m/s! Now we can solve for a: \[a={0-25 \over 40}=-0.625\] So the acceleration of the bus is -0.625 m/s^2. It's negative because the bus is slowing down. If you have any questions please ask!

OpenStudy (anonymous):

Thank you so much :) going to post another question if you would like to help again ty

OpenStudy (matt101):

No problem

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