Question

ques...

Answer 1

Area on the left side will be calculated as
\[A= \int\limits_{-1}^{-2}(x+1)dx \] or\[A=\int\limits_{-2}^{-1}(x+1)dx\]

Answer 2

well if you look at the left side.
What are your domains? You even wrote it out on your diagram above.

Answer 3

we are talking about the area of a function...whatever the integral function is, just integrate and take its modulus

Answer 4

it should be the second option bc i think the top number on the integral is usually the bigger number... so since -1 is bigger than -2 , -1 should be at the top and -2 on the bottom.

Answer 5

ok thx

Answer 6

no problem :)!

Answer 7

I actually did the ques and found out for left side you take limits right to left and for right you take left to right. So 1st option here

Answer 8

really? :O
I always did it differently then..

Answer 9

But as divu said, you can take whatever limits you want as you'll be doing mod of your answer as area is always positive

Answer 10

hmm interesting ^_^ Well you've taught me something new !

Answer 11

\[\left| \int\limits\limits_{a}^{b}dx \right| = \left| -\int\limits\limits_{b}^{a}dx \right|\]

Answer 12

that's correct yaaahh.

Answer 13

:)

Answer 14

if you try understand what is actually happening in the integration process, you will see that you always work left to right by convention. to illiustrate: