Question

A(aq)+B(aq)⇌2C(aq)
what directions will the equation shifts when we double both B and C?
what directions will the equation shifts when we double A, half B?
Can someone explain it to me?

Answer 1

you have to write down the mass action law for the reaction and give any value for the concentrations of A, B, C, (I would choose 1M to make the calculations easy) and calculate the K. Then calculate the Q with the same formula but now double the concentration of C and B (2M each), If the Q is bigger than the K the reaction will move to the left, if the Q is smaller than the K the reaction will shift to the products (right), if K=Q the reaction it is at equilibrium.
For the second part of the question you can calculate the Q with the double of A concentration (2M) and half of B (0.5) and compare this new value with the K .

Answer 2

Are you familiar with Le'Chatliers principle?

Answer 3

If we're assuming this system is in dynamic equlibrium (for simplicity) which i am 100% sure it is, then you can apply le'chatliers principle which basically helps you determine where the direction of the equilibrium will shift by telling you that it will shift in the opposite direction to sort of balance that offset change that was brought about.

According to his principle, I'm assuming you mean double the concentrations of both B or C?
Chatliers principle states that if you increase the concentration of one species, it must favor the reaction side in which that species is consumed.

Keep in mind the product being formed, and the amount there is.
for every A reacting with 1 B, you form 2 C products.

Answer 4

I am not familiar with finding Q and K as we haven't cover Le'Chatliers principle in class.
I only know that when the concentration of a compound increases, it will shift to the direction that will decrease the concentration in order to achieve equilibrium

Answer 5

can you explain more?