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Mathematics 7 Online
OpenStudy (anonymous):

I NEED MAJOR HELP FOR GEOMETRY!! WILL FAN+MEDAL!!

OpenStudy (anonymous):

Using the image below, find the y value for the point that divides the line segment XY into a ratio of 1:2. Segment XY is shown. X is at negative 6, negative 1 and Y is at 5, 1 −0.7 −2.3 −0.3 −0.2

OpenStudy (anonymous):

all the answers are negative

OpenStudy (anonymous):

OpenStudy (anonymous):

@tkhunny

rishavraj (rishavraj):

its about internal division......u know tht???

rishavraj (rishavraj):

@rosebud4612flvs ?

OpenStudy (anonymous):

I think the answer is -0.3

rishavraj (rishavraj):

yup.....:))

OpenStudy (anonymous):

awesome :) thank you :) can you help with one last question?

rishavraj (rishavraj):

yup....i will try..:)

OpenStudy (anonymous):

Find the perimeter of the image below: Figure ABCDE is shown. A is at 2, 0. B is at negative 4, 5. C is at 4, 10. D is at 8, 7. E is at 4, 5 32.1 units 35. 8 units 37.6 units 39.2 units

OpenStudy (anonymous):

OpenStudy (anonymous):

thank you :)

OpenStudy (anonymous):

I'm not sure how to do this one; I know what perimeter is, I just don't know how to apply it to this shape.

rishavraj (rishavraj):

just add the side lengths....

OpenStudy (anonymous):

I did but i got 24 :/

rishavraj (rishavraj):

length of BC???

OpenStudy (anonymous):

8?

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

that BC=8

OpenStudy (anonymous):

Im not sure how to do this

rishavraj (rishavraj):

how???? BC = \[\sqrt{(-4 - 4)^2 + (5 - 10)^2}\]

OpenStudy (anonymous):

Oh, BC would equal 89?

OpenStudy (anonymous):

Do I do that to sides BA, AE, ED, & DC too?

rishavraj (rishavraj):

BC = \[\sqrt{89}\]

OpenStudy (anonymous):

ok hold on

rishavraj (rishavraj):

okie dokie...:))

OpenStudy (anonymous):

ok so i got : BC=89 BA= 61 AE= 29 ED= 20 DC= 185

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

@rishavraj

rishavraj (rishavraj):

@rosebud4612flvs nah...:(( see distance between two points say \[(x _{1} , y _{1}) ~~~~ and ~~~ (x _{2} , y _{2}) \] is \[\sqrt{(x _{2} - x _{1})^2 + (y _{2} - y _{1})^2}\]

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