Question

Ellipse question

Answer 1

Do I start with the standard form of a ellipse?

Answer 2

I had a similar question I asked about a month ago, same idea but with a parabola: http://openstudy.com/users/swagmaster47#/updates/54e365f6e4b0bd4ff5b8b63e

Answer 3

I'd say yes, start off with the standard form, that is, that the cente is the origin

Answer 4

based on the graph
it looks like a "vertical ellipse", that is, the major axis is over the y-axis

that means, the "a" component, or the major axis, will be under the "y" in the equation, or \(\bf \cfrac{(x-{\color{brown}{ h}})^2}{{\color{purple}{ b}}^2}+\cfrac{(y-{\color{blue}{ k}})^2}{{\color{purple}{ a}}^2}=1\)

Answer 5

OK, so I have \[\frac{ (x - 0)^2 }{ a^2 }+\frac{ (y-0)^2 }{b^2 } = 1\]

Answer 6

lemme see.. .if I can give it a quick draw

Answer 7

I mean \[\frac{ (x - 0)^2 }{ b^2 }+\frac{ (y-0)^2 }{a^2 } = 1\]